Sort a dictionary by key or value in Python
Sorting based on a dictionary value or key is easy using Python.
Sort by value in a dictionary
In Python 3.7 and above, a combination of dictionary comprehension and sorted can be used:
1foo = {"first": 1, "third": 3, "second": 2, "zeroth": 0}
2print({k: v for k, v in sorted(foo.items(), key=lambda i: i[1])})In addition,
1foo = {"first": 1, "third": 3, "second": 2, "zeroth": 0}
2print(dict(sorted(foo.items(), key=lambda i: i[1])))Output:
1{'zeroth': 0, 'first': 1, 'second': 2, 'third': 3}sorted allows a optional keyword argument of key: a function to execute for ordering.
Sort by key in a dictionary
Similar to the technique before, the lambda argument can reference the 0th index to sort by the dictionary keys.
1foo = {"first": 1, "third": 3, "second": 2, "zeroth": 0}
2print({k: v for k, v in sorted(foo.items(), key=lambda i: i[0])})Output:
1{'first': 1, 'second': 2, 'third': 3, 'zeroth': 0}