Sorting based on a dictionary value or key is easy using Python.
Sort by value in a dictionary
In Python 3.7 and above, a combination of dictionary comprehension and sorted can be used:
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| foo = {"first": 1, "third": 3, "second": 2, "zeroth": 0}
print({k: v for k, v in sorted(foo.items(), key=lambda i: i[1])})
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In addition,
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| foo = {"first": 1, "third": 3, "second": 2, "zeroth": 0}
print(dict(sorted(foo.items(), key=lambda i: i[1])))
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Output:
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| {'zeroth': 0, 'first': 1, 'second': 2, 'third': 3}
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sorted allows a optional keyword argument of key: a function to execute for ordering.
Sort by key in a dictionary
Similar to the technique before, the lambda argument can reference the 0th index to sort by the dictionary keys.
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| foo = {"first": 1, "third": 3, "second": 2, "zeroth": 0}
print({k: v for k, v in sorted(foo.items(), key=lambda i: i[0])})
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Output:
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| {'first': 1, 'second': 2, 'third': 3, 'zeroth': 0}
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